1) If $p_1$$p_2$,...,$p_k$ be different primes and m = product of primes $p_1$,$p_2$,...,$p_k$ . How to prove that, when N = $N_1$ + $N_2$+...+$N_k$, where the prime factors of $N_i$ (here i is running from 1 to k) are exactly {$p_1$,$p_2$,...,$p_k$} \ {$p_i$} for each i, then (N, m) = 1.
2) For any given integer N with (N, m) = 1, use the Chinese Remainder Theorem to determine integers $M_i$ for which N is congruent to $M_i$ (mod m), where i is from 1 to k. The prime factors of $M_i$ are exactly {$p_1$,$p_2$,...,$p_k$} \ {$p_i$} and 1 < or equal to $M_i$ less than or equal to m,for each i.
I need complete discussion on both questions by proof or generalization.