Is it true that we can diagonalise a matrix iff eigenvectors are independent? I think so, but I'm not sure.
Clarification: lets say I, for some matrix A, find eigenvalues a, b, and c. The eigenvectors associated with those eigenvalues I will call a, b, c. We know that a ≠ b ≠ c <=> a, b, c are independent.
Now, my question is if this statement is true
a, b, c are independent <=> we can diagonalise a matrix A.