So we are learning trigonometry in school and I would like to ask for a little help with these. I would really appreciate if somebody can explain me how I can solve such equations :)
$\sin 3x \cdot \cos 3x = \sin 2x$
$2( 1 + \sin^6 x + \cos^6 x ) - 3(\sin^4 x + \cos^4 x) - \cos x = 0$
$3 \sin^2 x - 4 \sin x \cdot \cos x + 5 \cos^2 x = 2$
$\sin^2 x - \sin^4 x + \cos^4 x = 1$
In our students book they're poorly explained with 2 pages, I tried to find a solution on the web, but still couldn't find similar examples. All we got from our teacher was paper with few formulas and we basically have no idea when to use them. I would show what I've tried, but the problem is that I have no idea to even start solving such equations.