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There are two sides of a rectangle with one large and other small. A person walks along the diagonal and saves $1/3$ rd of larger side. Difference between larger and smaller size is $196$. then area of the triangle is ???

My Try :

let the larger side is : $l$

then the smaller side is :$l-196$


$l^2 + (l-196)^2 = (l-l/3)^2$

=>...... ...... .......


now i can't solve it

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It may be better to let the smaller side be $x$ and the larger side be $y$. – André Nicolas Feb 18 '14 at 8:20
please it will help???and whats wrong in my approach – Ritabrata Gautam Feb 18 '14 at 8:24
Nothing wrong with your approach, though you got the "save one-third" equation wrong. Having two variables sometimes makes calculations easier. – André Nicolas Feb 18 '14 at 8:25
up vote 2 down vote accepted

The hypotenuse is not $l-l/3$ but $l+(l-196)-l/3$

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how????its given that A person walks along the diagonal and saves 1/3 rd of larger side – Ritabrata Gautam Feb 18 '14 at 8:21
please explain whats wrong in my approach – Ritabrata Gautam Feb 18 '14 at 8:24
(1) the hypotenuse must be more than the larger side and (2) the saving is comparing walking the hypotenuse against walking both the larger and the smaller side – Henry Feb 18 '14 at 8:25
ohh... now i many thanks to both of you – Ritabrata Gautam Feb 18 '14 at 8:28

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