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There are two sides of a rectangle with one large and other small. A person walks along the diagonal and saves $1/3$ rd of larger side. Difference between larger and smaller size is $196$. then area of the triangle is ???

My Try :

let the larger side is : $l$

then the smaller side is :$l-196$

then,

$l^2 + (l-196)^2 = (l-l/3)^2$

=>...... ...... .......

$=>l^2-252l+24696=0$

now i can't solve it

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It may be better to let the smaller side be $x$ and the larger side be $y$. –  André Nicolas Feb 18 at 8:20
    
please explain...how it will help???and whats wrong in my approach –  Ritabrata Gautam Feb 18 at 8:24
    
Nothing wrong with your approach, though you got the "save one-third" equation wrong. Having two variables sometimes makes calculations easier. –  André Nicolas Feb 18 at 8:25

1 Answer 1

up vote 2 down vote accepted

The hypotenuse is not $l-l/3$ but $l+(l-196)-l/3$

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how????its given that A person walks along the diagonal and saves 1/3 rd of larger side –  Ritabrata Gautam Feb 18 at 8:21
    
please explain whats wrong in my approach –  Ritabrata Gautam Feb 18 at 8:24
1  
(1) the hypotenuse must be more than the larger side and (2) the saving is comparing walking the hypotenuse against walking both the larger and the smaller side –  Henry Feb 18 at 8:25
    
ohh... now i understand..so many thanks to both of you –  Ritabrata Gautam Feb 18 at 8:28

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