# Exponents and fractions pre-calculus

How would I go on about solving this:

# ${x^4y^7\over x^5y^5}$

When $x = {1\over3}$ and y = ${2\over 9}$

My working out:

Firstly I simplify.-

Then substitute

Further,

and

# ${{4\over243} \over{1\over3}}$

since $a/b / c/d = ab * dc$:-

equals

Simplified:

# ${4\over81}$

The correct answer is

# ${4\over27}$

Can someone help me employ the proper method in solving this problem?

Regards,

-
The initial simplification should be to $\frac{y^2}{x}$. –  André Nicolas Feb 5 at 5:14

The first step is $$\frac{y^2}{x}$$ So the answer is $$\frac{4/81}{1/3}= \frac{4 \cdot 3}{81} = \frac{4}{27}$$
You just had the extra $x$. Must be an oversight