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In Hatcher's notes on 3-Manifolds (available here), he constructs Seifert-fibred spaces in the following way:

Let $S$ be some surface, possibly with boundary (let's say with boundary for now). Let $M'$ be the oriented circle bundle over $S$. Now to some (or all) of the torus boundary components of $M'$, we can "sew" a solid torus $N$ as follows. First, call the boundary component in $M'$ we're focusing on $T$. Let $D$ be a meridional disk in $N$ with boundary $\delta D$, and attach $\delta D$ to a simple closed curve in $T$ of slope $\frac{\alpha}{\beta}$ (here slope means when I lift this simple closed curve to the universal cover $\mathbb{R}^2$, the line has slope $\frac{\alpha}{\beta}$). I fill in the rest (a 3-ball) in an essentially unique way. After I've done all the attaching I want, I get a Seifert-fibred space $M$.

My question is: how can I get a presentation for $\pi_1(M)$ from the knowledge of $S$ and the slopes? For example, if $S$ is a disk, then $M'$ is just a solid torus. Attaching another solid torus with slope $\frac{p}{q}$ gives the lens space $L_\frac{p}{q}$. If $t$ represents a longitudinal circle in $M'$, then $\pi_1(M')=\langle t\rangle$ and for $M$ we simply add the relation $t^q=1$. But things can't be that easy!

Because if $S$ is an annulus, then $M'$ is just $S\times S^1$; now suppose we want to fill in the two boundary components of $M'$ with two solid tori $N_1$ and $N_2$, using slopes $\frac{a}{b}$ and $\frac{e}{f}$. If $t$ represents a longitudinal circle in $M'$ and $d$ a meridional circle, then $\pi_1(M') = \langle t,d\ |\ [t,d]=1\rangle$. I want to believe that I then get $\pi_1(M)=\langle t,d\ |\ [t,d]=1, d^a=t^b, d^e=t^f\rangle$, but this is not true.

So what is the appropriate way to get the fundamental group of $M$ from the fundamental group of $M'$? To be overly specific, where does the Euler number come in?

Thanks!

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Have you tried playing around with the homotopy long exact sequence? –  Neal Sep 19 '11 at 10:39
    
In the tag merging and synonyms thread on the meta there was a decision that [3-manifolds] should be merged into [low-dimensional-topology]. No reason to use both tags on the same question. –  Asaf Karagila Sep 19 '11 at 22:44
    
@AsafKaragila: Ah, thank you! I was wondering why I couldn't find it :) –  user641 Sep 19 '11 at 23:30
    
You use the Seifert - VanKampen theorem. It was designed precisely for situations like this. –  Ryan Budney Sep 20 '11 at 0:07
    
@RyanBudney: I would like to do that! But for example, look at the annulus example I gave in the bottom of my post: there I used van Kampen's theorem, thinking that attaching this 2-disk is simply adding a relation, and the rest of the 3-ball doesn't affect the group. However, the presentation I end up with is not correct. So my question is: what went wrong? –  user641 Sep 20 '11 at 0:23
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