(Probably) A Simple Set Theory Question

Let $U = \{a,b,c,...,x,y,z\}$ with $A=\{a,b,c \}$ and $C=\{a,b,d,e \}$. If $|A \cap B| = 2$ and $(A \cap B) \subset B \subset C$, determine $B$.

This question doesn't seem complete. Am I right, and if not, what is the answer?

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What does $X \subset Y$ mean: "$X$ is a subset of $Y$" or "$X$ is a proper subset of $Y$"? – Srivatsan Sep 16 '11 at 14:00
>If C, D are sets from a universe U, C is a subset of D, written C ⊆ D, or D ⊇ C, if every element of C is an element of D. Additionally, if D contains an element that is not in C, then C is called a proper subset of D, denoted C ⊂ D or D ⊃ C. – a930913 Sep 16 '11 at 14:04
The question seems ambiguous. B can be either {a, b, d} or {a, b, e}. – Zach Langley Sep 16 '11 at 14:07
a930913 Yes, the terms subset and proper subset are standard and I understand them. On the other hand, the notation $\subset$ is used to mean both "subset" and "proper subset" (depending on who uses it). That's why I commented asking you to clarify what you mean by it. (Some people, like me, use the more emphatic notations $\subseteq$ and $\subsetneq$, avoiding $\subset$ altogether.) – Srivatsan Sep 16 '11 at 14:10

Hint: $c \not \in B$, so what is $A \cap B$? But I don't see how you can tell the difference between $d$ and $e$. If $\subset$ is proper subset you can get pretty close.
If inclusion is proper then $B=\{a,b,d\}$ or $B=\{a,b,e\}$ and if inclusion covers equality, than one could add $\{a,b\}$ and $\{a,b,d,e\}$.