I came across this equation.
$m = (m + 1/2)x + (b-1)$
The goal is to solve for m and b.
I want to make sure I understand the very last algebraic step required. Since the two sides are equal, you force the first term to equal 0, thereby having m equal the 2nd term. ie: You set m = -1/2 and then m must equal (b-1) You subsequently sub in that m=-1/2 to solve for b.
It makes sense once I see it, but am not sure I'd think of that. Is there a name for this technique? Is this the only possible solution? What is the general strategy?
You intentionally pick m=-1/2 to conveniently get rid of that m ?
To solve for 2 variables, you MUST get rid of the 3rd (x)?