Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

Represent $\sqrt{2}$ in the form $$\sqrt{2}=1+\frac{8}{A_1+\displaystyle\frac{8}{A_2+\displaystyle\frac{8}{A_3+\ddots}}},$$ where $A_n$ is a positive integer and $A_n \geq 8$ for all $n$. So we have $A_1=19$, $A_2=25$, $A_3=15$ and so on. Is the sequence $\left(A_n\right)_{n=1}^\infty$ bounded? How to proof? Thank you.

share|improve this question
Why?????????????????????????????? –  Will Jagy Jan 15 '14 at 20:49
I would think not. –  Balarka Sen Jan 15 '14 at 20:58
Here are some more terms: oeis.org/A087951 –  Matthew Conroy Jan 15 '14 at 21:22
Help me please. –  kong Jan 18 '14 at 14:32

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Browse other questions tagged or ask your own question.