Is the algebraic norm of an euclidean integer ring is also an euclidean domain norm?

Let K be a finite extension of $\mathbb{Q}$ (a number field) and $\mathcal{O}_K$ its ring of integers. One defines the norm of an element $\alpha\in K$ to be the determinant of the transformation $m_\alpha: K\to K$ of multiplication by $\alpha$ (where $K$ is considered as a vector space over $\mathbb{Q}$).

Now sometimes the integer ring is also an euclidean domain, i.e. it has a "euclidean norm" satisfying the defining property of division algorithm. My question is: in an integer ring which is also euclidean, will the norm defined above also serve as an euclidean norm?

Put otherwise: is there an example for an euclidean integer ring whose norm is not an euclidean norm?

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2 Answers

Wikipedia says that "$\mathbb Q(\sqrt {69})$ is Euclidean but not norm-Euclidean. Finding all such fields is a major open problem, particularly in the quadratic case."

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It is always nice to find out you've stumbled unaware on a "major open problem". –  Gadi A Sep 12 '11 at 11:58
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This paper seems to answer the question but your answer should give some detail. Don't expect people to just click on links. –  lhf Sep 12 '11 at 11:18