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How can you show that the non-principal prime ideals of $\mathbb{Z}[x]$ can be generated by only two elements, a prime number $p$ and an irreducible polynomial not in $p\mathbb{Z}[x]$?

I can get to the point in the proof that a prime ideal with more than one generator must contain some $p$, but I can't prove that appending the polynomial can generate the prime ideal itself.

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marked as duplicate by Najib Idrissi, SHOBHIT GAUTAM, Jeremy Rickard, David K, Mike Miller Feb 8 '15 at 17:15

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

HINT $\ $ The image of the ideal in $\rm\:\mathbb F_p[x]$ is principal. Pull this information back to $\rm\:\mathbb Z[x]\:.$

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