# Arithmetic Order of Operation

What is the square root of -4 + 13 x 8 - (7 + 2(3 + 20/5))

The answer seems to be 3 but I wanted help trying to get to the answer!

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$3 + 20/5 = 7$, so $(7 + 2(3 + 20/5)) = 7 + 2\cdot 7 = 21$. We then have $-4 + 13 \cdot 8 - 21 = 79$, and it gives $\sqrt{79}$. – user61527 Jan 14 '14 at 6:39
welcome to mathematic forum,but for such simplest arithmetic terms,please pay more attention before ask it – dato datuashvili Jan 14 '14 at 6:39
@Raphaela i have answered and please see it – dato datuashvili Jan 14 '14 at 6:42
and last note for the future ,please whenever your problem is solved,show it others by accepting this answer,which helped you,because it will encourage others to help you and also your reputation would be increased.good lucks – dato datuashvili Jan 14 '14 at 6:49

using BODMAS :

$$-4+13*8-(7+2(3+20/5))$$ $$-4+13*8-(7+2*7)$$ $$-4+13*8-(7+14)$$ $$-4+13*8-21$$ $$-4+104-21$$ $$79$$ now squre root $79$

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+1 for your help @ fazla Rabbi Mashrur – dato datuashvili Jan 14 '14 at 6:50

ok let us calculate seperately

first in brackets

1.20/5=4

2.3+4=7

3.2*7=14

4.7+14=21

5.13*8=104

6.104-21=83

7.83-4=79


$\sqrt{79}=8.888194417315589$

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