Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I am not sure what the domain of $\displaystyle \arcsin \left(x - \frac{2}{3}\right)$ is.

I know that the domain for $\arcsin$ is $[-1, 1]$, but how can I use this to find the domain of the function above?

share|cite|improve this question
To be more accurate, the function arcsin$(t)$ has domain $t\in [-1,1]$. Your function is arcsin$(t)$ where $t = x-2/3$. So you want to find values of $x$ such that $(x-2/3)\in [-1,1]$. – andraiamatrix Jan 12 '14 at 3:34
up vote 0 down vote accepted

Hint: what values of $x$ would make $\displaystyle x - \frac{2}{3}$ be within the domain of $\arcsin$?

share|cite|improve this answer
hmmm i see, thank you – marck Jan 12 '14 at 4:11

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.