Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

I've done the code that generates all the solutions. But know I am suppose to filter out any redundant solutions based on symmetry and rotations. I have code for vertical symmetry, horizontal symmetry, rotation 90,180 and 270. The bit that remains is removing symmetry about the the diagonals. / and \ of the board. I guess I can rotate it 90 degress instead of making code for both diagonals. I want to implement the diagonal "\". I drew up some points.
From bottom part to the upper part.
(1,3) -> (6,8)
(2,1) -> (8,7)

From top part to bottom part.
(4,6)->(3,5)
(5,6)->(3,4)

I'm not sure what formulas would do this for me. And what about chess pieces on the diagonal it self, they would just stay put I guess?

share|improve this question
    
My code gives 23 "unique" answers without filtering for the diagonal ones. –  Algific Sep 11 '11 at 12:43
    
I need it to work with a n*n board. –  Algific Sep 11 '11 at 13:50

1 Answer 1

up vote 2 down vote accepted

$(a,b)\to(9-b,9-a){}{}{}{}{}{}$

share|improve this answer
    
Now I just feel stupid haha. How would it be if the diagonal went the other way? "/"? –  Algific Sep 11 '11 at 13:50
1  
@Algific: for the diagonal "/" it is (a, b) -> (b, a). –  Jiri Sep 11 '11 at 14:17

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.