I'm about to cry. I can't get this and it's frustrating beyond belief. Here's a problem in my homework:

Oasis B is a distance d = 9 km east of oasis A, along the x axis shown in the Figure. A confused camel, intending to walk directly from A to B instead walks a distance W1 = 23 km west of due south by angle θ1 = 15.0°. It then walks a distance W2 = 33 km due north. If it is to then walk directly to B, (a) how far (in km) and (b) in what direction should it walk (relative to the positive direction of the x axis)?

I've drawn something that looks like this:

              |
|    |
|    |
|    |
---------|----a-------------b
|   /|
|  / |
| /  |
|/   |

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Your drawing looks right to me. The problem specifies the direction of the axes, but not where the origin is. Therefore you can place the origin wherever it is convenient for you; I suggest to declare $B$ to be the origin. Then $A$ is at $(-9, 0)$. Express each of the camel's two legs as travel as vectors and add them to $A$; then you find the coordinates it ends up at relative to $B$ ... – Henning Makholm Sep 3 '11 at 21:54

The "vector" part of this problem is to break down where the camel is walking into two components: a component which is only concerned with north-south travel, and a component which is only concerned with east-west travel.

You have the initial angle that the camel is walking: 15° west of due south; and it travels 23km. Using trigonometry, you can determine how much W of that 23km is just going westward, and how much S is just going southward. (Note that these two components don't add to 23km! Using Pythagoras' theorem, you should be able to see that W2 + S2 = (23km)2 .) So first, determine W and S. This will give you the position (call it C) of the camel after it's first blundering attempt to go to B.

Note that the usual convention is to describe west as being (negative east), and south as being (negative north). That is, because the camel is heading south and west, you should be able to describe its position in terms of a negative distance north, and separately a negative distance east.

The camel then starts going due north; it should be easy to find out where it ends up after that leg of the trip, because all of that leg is invested in north-south travel; you can just add that to the north-south component of the camel's position, to get its position D after the second leg.

Now you know where the camel is after the second leg of it's haphazard odyssey. Construct a right-angle triangle with the corners at B and D, and with the two shorter sides parallel to the x and y axes (that is, horizontal and vertical; or north-south and east-west). You should be able to apply Pythagoras' Theorem to find out how far away D is from B; that is, how far the camel has to travel to finally arrive where it was supposed to go. And for the direction, use trigonometry to find out the angle that it must travel, relative to east (which is the positive direction of the x axis).

Good luck!

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Thank you for helping me understand this! – Rampage Sep 3 '11 at 22:20