# How can a negative multiplied by a negative give positive? [duplicate]

On first look this can seem weird. But I can explain what I am looking for.

We all know from elementary maths that $(-\times-)=+$.

Now, lets say there are 3 cows and I say they will become doubled after one year so $3*2=6$.

And lets say I have $-3$ cows(which is not possible, bcoz I can show $3$ cows but not $-3$) and if I multiply it by $-2$, I get $-3\times -2=6$. How is it possible?, nothing multiplied by nothing equals something!?

Some said the reason belongs to philosophy, if yes, what's the idea behind it?

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## marked as duplicate by TZakrevskiy, Thomas Andrews, Brian Rushton, Old John, hardmathDec 19 '13 at 14:41

Think money. Negative means your in debt. So if your in debt 3 and in a year you put your debt holder in debt by double the amount then $-3(-2)=6$. – Wintermute Dec 19 '13 at 12:38
I think multiplying negatives is what makes sense. If you extend the monoid which is $\mathbb{N}$ to $\mathbb{Z}$ and take the bilinear extension of what is multiplication on $\mathbb{N}$, then you end up with this fact. – sebigu Dec 19 '13 at 12:41
Maybe you at least agree that $3\times (-2) = -6$. Then note that $(-3)\times (-2)$ should be a number such that $(-3)\times (-2) + 3\times (-2) = \bigl((-3)+3\bigr)\times(-2) = 0\times(-2) = 0$, so it must be $+6$ because only $+6+(-6) = 0$. – Hagen von Eitzen Dec 19 '13 at 12:46
@TCSLearner Nope, multiply by $-2$. Your putting someone else in debt. If you multiply by 2 you are doubling your own debt. You can also think about a minus sign as a type of direction. If you go 3 units to the left of 0 your are at -3. If you go twice the amount of units in the opposite direction your are at 6. So multiplication by $-2$ says you want to travel in the reverse direction. – Wintermute Dec 19 '13 at 12:51
– Jean-Claude Arbaut Dec 19 '13 at 13:15

It's best to think, perhaps, of the negative sign as a "change in direction". The default direction is to the positive end of the number line (to the right). So $3\times 2$ moves us six units to the right, to land at $6$.

$-3\times 2$ changes direction and moves us $6$ units to the left of zero, to land at $-6$.

$-3 \times -2 = -(-3 \times 2)$ reverses our direction once again, taking us back to the right six units from zero, the opposite direction than does $-3 \times 2$ in the amount of $6$ units to the right. So in the end, we are at the "same position" whether we use $3\times 2$ or $-3\times -2$.

Note that our use of arithmetic, in a practical sense, depends on the context in which we are applying it. So your example is just a poor context to apply multiplication of negative numbers, since, of course, it seems absurd to think of having $-3$ cows. But negative numbers can represent position, with respect to some point of origin, as I noted in the number line example above. And time can be represented in terms of the past (negative time), now (the point of reference), and the future (positive values for time). Similarly, in finance, negative numbers can represent debt or loss, while positive numbers represent profit, or gain. I'm sure if you put your thinking cap on, you'll see that mutltiplication of negative numbers certainly can, and does make sense.

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Yup, I agree with your argument. – Brainy Dec 19 '13 at 13:11
Glad to have helped! ;-) – amWhy Dec 19 '13 at 13:13

Multiplication by a positive number is rather intuitive, so $(+ \times +)$ and $(+\times -)$ are relatively easy (for the latter, think you multiply a debt, for example). So the hard one is $(- \times -)$. I may be uneasy to understand this directly, but if you want to keep laws of arithmetic as they are with positive numbers, then

$$a \times (b + c) = a \times b + a \times c$$

With $c=-b$, it yields

$$0 = a \times 0 = a \times b + a \times (-b)$$ $$a \times b = - (a \times (-b))$$

Now, if both $a$ and $b$ are negative, you must have on the left $(- \times -)$, and on the right, the negation of $(- \times +)$, thus a positive number.

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