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My approach: $m<A= 60$ degrees and $m<C=30$. This creats a 30, 60, 90 triangle with ratios $$1:\sqrt3:2$$

After getting the ratio's of the areas, I obtain $$\frac{b*h}{\pi r^2}=\frac{1*\sqrt 3}{\pi 1^2}=\frac{\sqrt 3}{\pi}$$

Anybody else get the same result? I'm not sure if I'm correct. Thanks

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you are right.what makes you not sure? –  chenbai Dec 18 '13 at 4:21
    
nije pere gechhis jokhon tokhon diechhis keno problem ta;badmaishkesta user69127 –  krishan Dec 18 '13 at 8:17
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