# A group of order 561 is cyclic.

Prove that any group of order 561 is cyclic.

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As you are a new user I would like to tell you that : It would not be enough to just write the question to get a reply... please explain what you have tried? – Praphulla Koushik Dec 13 '13 at 7:17
15 not prim but is cyclic. – ayoob Dec 13 '13 at 7:20
@Magdiragdag : fine fine :) – Praphulla Koushik Dec 13 '13 at 7:23
@ayoob: At least you should describe your background, what did you learn and what difficulties did you encountered so that you know what hints and answers should be given. – John Ma Dec 13 '13 at 7:27
N(H)/C(H) -----> AUT(H) normalizer - central theorem – ayoob Dec 13 '13 at 7:31

In general, there is only one group of order $n$ iff gcd$(n,\varphi(n))=1$. Of course such a group must be necessarily cyclic. 561 satisfies the condition.