Given a circle with 24 evenly spaced points, how would you find the number of possible isosceles triangles (which includes equilateral) that can by drawn using the points?
My attempt was to say that the number of ways to pick the vertex where the congruent sides meet is 24. For each of the vertexes there are 11 possible pairs of other vertices. This gives 264 possible triangles, but I don't think I did it right. Can anyone help?