Anyone here who can give me some help about creating formula with these rules?
- $X$ is given to find $Y$
- $Y ≤ X$
- $Y$ cannot be equal $0$ -
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It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, see the FAQ.
$f(x)=1$ if $x=1$, else $f(x)=x-1$. Satisfies all the properties except the contradiction between $y\lt x$ and $x=1$ implies $y=1$.
EDIT: Now that the question has been edited, this answer satisfies ALL the conditions. So, Ran, is this the kind of answer you want? or are there some other conditions you've forgotten to mention?