Anyone here who can give me some help about creating formula with these rules?
- $X$ is given to find $Y$
- $Y ≤ X$
- $Y$ cannot be equal $0$ -
closed as not a real question by mixedmath♦, Qiaochu Yuan Aug 29 '11 at 18:46
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question.
|show 4 more comments|
$f(x)=1$ if $x=1$, else $f(x)=x-1$. Satisfies all the properties except the contradiction between $y\lt x$ and $x=1$ implies $y=1$.
EDIT: Now that the question has been edited, this answer satisfies ALL the conditions. So, Ran, is this the kind of answer you want? or are there some other conditions you've forgotten to mention?