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1) I just want to know that my steps are correct or not? what are the missing steps. please help me.

2) Actually I can not simplify this is. So what are the missing steps at my trying path?

please help me.....enter image description here

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You can use for example \$ \overline{ab} \$ to write ab with a bar and to clear your question. – BIS HD Nov 27 '13 at 12:12

A few hints:

1) Your steps don't seem to be correct. As far as I can see, you can write

$$\bar b ( a(c + \bar c) + \overline{ac}) = \bar b (a + \bar{ac}) = \bar b a + \overline{abc}$$ How to proceed from here? How did you come to your answer?

2) Consider that $a + \bar a = $ true, for every $a$. So you can simplify a lot in your last expression.

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yes but i can not understand i read the Boolean rules. but not a good result. You are how to get that "a"? " -b(a(c+ -c) + -a-c) " – user111554 Nov 27 '13 at 12:52
  1. $\overline{abc + ab\overline{c} + \overline{a}b\overline{c}}$ = $\overline{b(ac + a\overline{c} + \overline{a}\overline{c})}$

=$\overline{b([ac + a\overline{c}]+ [a\overline{c}+ \overline{a}\overline{c}])}$ as $a + a =a$

=$\overline{b(a + \overline{c})}$

=$\overline{b} + \overline{a}c$ Using the De-Morgans Law

2.From 1, 3 terms you can eliminate a, 2&3 b, 3&4 c resulting in

$\overline{\overline{b}c + ac + ab} = (b + \overline{c})(\overline{a} +\overline{c})(\overline{a} +\overline{b})$

This can be multiplied and simplified further to the result

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