Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

This question already has an answer here:

I don't know the probability of rolling a large straight with 5 six-sided dice, so I need to know what the probability is. What is it?

share|cite|improve this question

marked as duplicate by Ross Millikan, vadim123, T. Bongers, Dominic Michaelis, Bruno Joyal Nov 26 '13 at 5:23

This question was marked as an exact duplicate of an existing question.

Matthew Conroy, it's about getting different consecutive numbers on every die in different ways – user111236 Nov 26 '13 at 4:53
But now I know! It's a 48 in 7,776 chance of rolling a large straight. – user111236 Nov 26 '13 at 15:04
I hope this answer is right, you know, the probability comment that's above this one that I answered yesterday (Tuesday, November 26, 2013). Also, why should comments typed in by yourself be edited up to 5 minutes? – user111236 Nov 27 '13 at 15:06

The probability of rolling 1-2-3-4-5 in that order is $(1/6)^5$. However any order will do, so it's $5!(1/6)^5$.

The probability of rolling 2-3-4-5-6 is similarly $5!(1/6)^5$.

Combining, we get $240(1/6)^5\approx 0.03$, i.e. about 3% of the time.

share|cite|improve this answer
Wow! That's amazing! Awesome! Fantastic! I can't believe you used a factorial and an exponent to figure that out! You also used a similarity thing! Another thing you used is an "approximately equal to" sign to approximate the answer. No doubt about it! – user111236 Nov 26 '13 at 15:01
You're welcome, glad to be of service. – vadim123 Nov 26 '13 at 15:14
But I didn't even say "Thank you." and how are you out of service? Also, how can you be glad when you're out of service?! – user111236 Nov 26 '13 at 16:24

Not the answer you're looking for? Browse other questions tagged or ask your own question.