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Is it possible for the number created by the consecutive numbers $1$ to $n$ where $n > 1$ be a palindrome eg. $1234567\ldots n$?

I believe this is a contest problem, but how would one solve this problem without looking up the hints?

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Just for clarification: by "the number created by ordering 1 to $n$", do you mean $$123456789101112\cdots n?$$ –  Zev Chonoles Aug 16 '11 at 22:58
    
@Zev: yeah that is what I mean –  Mark Aug 16 '11 at 23:06
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The easiest way is to look at the hint and then intensively study how you could have done it without the hint.. –  Listing Aug 16 '11 at 23:35
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@Robert: Re-ordering the number blocks apparently wasn't intended to be allowed. That said, since the answer to the original question is "no", it seems fair to ask about the case where re-ordering is allowed. –  Blue Aug 17 '11 at 3:24
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@Day, 1 19 8 17 6 15 4 13 2 10 20 12 3 14 5 16 7 18 9 11. –  Gerry Myerson Aug 17 '11 at 4:39

1 Answer 1

up vote 2 down vote accepted

A solution can be found on page 43 of Andreescu and Andrica, Number Theory: Structures, Examples, and Problems, which page I was able to access on Google Books.

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The link. –  J. M. Aug 17 '11 at 2:13
    
@J.M. You're the link man! –  Pedro Tamaroff Feb 18 '12 at 1:20

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