Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

Please help - in my notes, it is the group $V$ itself. I just want to confirm this. Can you also explain and give an example if that is possible?

share|cite|improve this question
up vote 9 down vote accepted

Every abelian group is its own center. If you look at the definitions you will see this.

share|cite|improve this answer
alright!! thanks! :)) – gggg Sep 30 '10 at 20:04

You know, this group has only 4 elements. You could just multiply them out. Really, there are only three worthwhile elements, as one is an identity and that commutes with everything.

It would take less than 5 minutes, and you could do it Cayley style or full-on multiplication table style. It would probably even be good for you, as you might get a feel for what groups really are.

share|cite|improve this answer
You're answering to a thread more than a year old. I hope OP has figured it out by now :) – t.b. Dec 13 '11 at 9:48
Besides - Cayley graphs don't make you feel what groups really are. – Martin Brandenburg Dec 13 '11 at 10:20
@t.b. Oh... Zev edited the question 14 hours ago, and I never pay attention to original post dates. So I thought I was answering an hour-old thread. Whoops. – mixedmath Dec 13 '11 at 22:46
@Martin: I never said cayley graphs would make him get a good feel, I said carrying out the multiplication would. I think this problem demonstrated a lack of understanding of group computation, that's all. – mixedmath Dec 13 '11 at 22:47

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.