Can anyone explain this wolframalpha result?
$ f(x)=\lim\limits_{h \to 0} \frac{-1}{(3x-2)^2} = \frac{-1}{(2-3x)^2}$
[lim ((-1)/((3x-2)^2)) as h->0] = [((-1)/((2-3x)^2)) ]
While this is not equal:
$ f(x)=\lim\limits_{h \to 0} \frac{-1}{(3x-2)^2} = \frac{-1}{(3x-2)^2}$
[lim ((-1)/((3x-2)^2)) as h->0] = [((-1)/((3x-2)^2))]
edit: addint $f(x)=$ to stop confusion about the lack of x in the limit.