# Using Rref to find the inverse of a matrix.

Since, I can't divide vectors to deduce an inverse matrix I have dismissed that approach. I did find that if I multiply all of the matrix row operators It will yield the inverse. Since I did the logic work to put my original matrix into RRef. I can use this approach. Problem is, I don't understand how to place the multipliers in the identity matrix to reflect the logic of the RRef process. Can any one help me , or post a link?

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Found a link to the Gauss/Jordan method. Let me see if I have this right. I set up the matrix just like I did for using RRef to find solution of a system of equations only I augment the Coordinate matrix with the Identity matrix and then I use the same RRef solution process. Am I understanding this right? – Chris Nov 4 '13 at 14:25
Do you have to find the inverse through Gauss method, or are you allowed to find through different linear algebra means? I am not talking about punching it into the calculator... – imranfat Nov 4 '13 at 14:43
This is to add things to my own back of tricks. I am trying to find AND understand the easiest way to do it. Gauss will let me find the inverse w/o screwing around with finding the determinant that gives it one thumbs up from me. – Chris Nov 4 '13 at 14:49
Are you familiar with the Characteristic equation and Cayley Hamilton Theorem for matrices? – imranfat Nov 4 '13 at 14:52
No I am not. But one thing I have learned recently is, the more advanced the math the simpler the solution. Well at least when you understand the process. So this sound really cool. Care to give a tinkerer a lesson? – Chris Nov 4 '13 at 14:54