Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

This question already has an answer here:

I understand that uni-variate polynomial rings with coefficients in a field only have principal ideals. For example, $\mathbb{C}[x]$. But how can I tell if an ideal of integer polynomial ring is principal, please? For example, a textbook claims that "the kernel of the map $\mathbb{Z[x]} \rightarrow \mathbb{Z[i]}$ sending $x \mapsto i$ is the principal ideal of $\mathbb{Z}[x]$ generated by $f=x^2+1$" without any justification. How to show this is true, please?

share|cite|improve this question

migrated from Oct 25 '13 at 0:24

This question came from our site for professional mathematicians.

marked as duplicate by T. Bongers, lhf, anon, Nick Peterson, Stefan4024 Oct 25 '13 at 1:12

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

up vote 1 down vote accepted

The quote tells you the element $f\in Z[x]$ that generates the ideal. Suppose now another $g\in Z[x]$ is in that ideal. Since $f$ is monic you can use Eucledian algorithm to find $h,r\in Z[x]$ such that $g=fh+r$, and $deg(r)\leq 1$. Since degree 0 or 1 polynomial are in said kernel conclude that $r\equiv 0$, therefore all elements $g$ of the ideal have form $fh$ for some $h$, therefore the ideal is generated by $f$.

share|cite|improve this answer

Not the answer you're looking for? Browse other questions tagged or ask your own question.