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Solve for x :

Tried to factorize and used substitution but no result.

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There's no equation there, so there's nothing to solve. – user61527 Oct 17 '13 at 6:43

1 Answer 1

up vote 4 down vote accepted

I’m assuming that the problem is to solve


Here’s a very elementary approach that will work if there is a nice solution. Since there is no rational root, we have no easy way to find a root $r$ and divide out $x-r$ to reduce the problem to that of solving a cubic equation. We can hope, though, that the lefthand side is a product of the form


where clearly $cd=4$. If we’re really fortunate, the coefficients will be integers. For no good reason I decided to try first the possible factorization


setting it equal to the original quartic and equating coefficients:



$$\left\{\begin{align*} &a+b=-6\\ &ab+4=12\\ &2(a+b)=-12\;. \end{align*}\right.$$

The third equation is equivalent to the first, so we want to solve the system

$$\left\{\begin{align*} &a+b=-6\\ &ab=8\;. \end{align*}\right.$$

It has a nice solution, so I’ll leave the rest to you, since it’s all quite straightforward. Note that I was fortunate: I picked the right factorization right off the bat. Had I tried


for instance, I’d have found myself with an inconsistent system. (Of course I was extremely lucky that there actually is a factorization of the form $(1)$ with integer $c$ and $d$.)

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