# Double integral convert in polar coordinates [closed]

Calculate the double integral by transferring to polar coordinates: $$I = \int_0^{5} \int_{0}^{\sqrt{\vphantom{\huge a}25 - x^{2}\,}} \ln\left(1 + x^{2} + y^{2}\right)\;{\rm d}y\,{\rm d}x$$

Make a sketch of the domain of integration. Present your answer in exact form and then evaluate it using a calculator up to two decimal places.

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At least give your own try instead of having someone else completely solve your problem/homework. Kind of beats the philosophical position of the universe to do this. –  teodron Oct 16 '13 at 7:12
I am very curious what goes through the mind of someone who posts something like this. I see these posts all the time, but I really just don't understand. You have copied an assignment, and given no indication what you expect anybody to do with it, or asked for any kind of help in particular, or suggested that you might be grateful for other people's time, or even said anything that makes you sound like a person! There is even an instruction to make a sketch! I am not offended, and I am not trying to criticize, I am honestly curious: what are you thinking? –  User-33433 Oct 16 '13 at 7:14
Welcome to math.SE, and thanks for your participation. You will benefit from reading how to ask a good homework question. People are generally eager to answer good questions here, and context is what makes any question a "good" question. You can click edit at any time and improve your post with some context. For any general question how to ask a good question is another enlightening read. –  J. W. Perry Oct 16 '13 at 7:21
Plz anybody help me to solve question? –  Patel Hetal Oct 16 '13 at 7:26
@PatelHetal: Yes –  B. S. Oct 16 '13 at 7:38

## closed as off-topic by The Chaz 2.0, Stefan Hansen, Lord_Farin, mau, Davide GiraudoOct 16 '13 at 9:00

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – The Chaz 2.0, Stefan Hansen, Lord_Farin, mau, Davide Giraudo
If this question can be reworded to fit the rules in the help center, please edit the question.

$$\theta|_0^{\pi/2},~~r|_0^5,~~x^2+y^2=r^2, J(x,y)=r$$
@PatelHetal: The $\theta$ and $r$ are independent of each other here so you need just to find the inside integral by taking $1+r^2=u$ and so $$\int_1^{26}\frac{\ln(u)du}{2}$$ and then multiply it by $\pi/2$. –  B. S. Oct 16 '13 at 8:21