# Triangle area division

It is given that in a triangle ABC, a line from A to BC intersects BC at point D. If the ratio in which AD divides BC is given can we say anything about the ratio of areas of triangle ABD and triangle ADC ?

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Area of triangle $ADC$=$$(AD*DC*Sin\theta)\over2$$ Area of triangle $ABD$=$$(AD*DB*Sin(180-\theta))\over2$$ [$\theta$ is the angle $ADC$]