# how to properly calculate difference in percent

Suppose, you have

x=8
y=10


Then y is 25% more than x, if x is used as the "base" value. If y ist the base, then x is 20% less than y.

So if I want to say, that the difference between x and y is ... percent, what value could I use? I can think of using 22.5% being in the middle between 20% and 25%, but that does not feel well-founded.

Should I not use percentages at all?

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"the difference between x and y is ... percent" - of what? – J. M. Jul 16 '11 at 13:13
@J.M., so you are asking for a "base" (do you call it that?) as well. I thought, I could do without. But @Sylverdrag 's answer suggests otherwise. – Sebastian Langer Jul 16 '11 at 13:37
If you want to avoid a base, then you could take the logarithm of the quotient (i.e. the difference of the logarithms), since $\log_e \frac{10}{8} \approx 0.22314\ldots$ and $\log_e \frac{8}{10} \approx -0.22314\ldots$, but this is not a percentage. – Henry Jul 16 '11 at 22:58
This is an interesting idea, @Henry! Thank you. – Sebastian Langer Jul 19 '11 at 0:43

I think, I understand. So I could probably do the following: Take the mean between x and y and then calculate the ratio between y-x and the mean? What I mean is $\left| \frac{y-x}{(x+y)/2} \right|$ . – Sebastian Langer Jul 16 '11 at 13:40