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How to create number 6 using only three 0, any arithmetic operation is allowed? I know it is possible, but I don't know how...

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$(0! + 0! + 0!)!$ – Daniel Fischer Oct 7 '13 at 13:02
Thanks, I think that is it! – Johnny Bre Oct 7 '13 at 13:06
Chop two of the zeros into two semicircles, put them back together as 3s. Then 3+3+0=6 – Michael Oct 7 '13 at 13:08

Daniel Fischer's answer of $(0! + 0! + 0!)!$ is probably the best answer, however if we're allowed to use any function that is commonly expressed as a symbol (e.g. sqrt, abs, ceil) then we can express $6$ using only a single $0$ like so : $\lceil |\sqrt{-0!}!!|\rceil ! = \lceil | i!!|\rceil ! = \lceil \approx 2.7\rceil ! = 3! = 6$

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I'm not sure about that, I don't think functions should be used. It could be lot easier if they could. – Johnny Bre Oct 7 '13 at 13:03
I would argue that $\cos{0}$ is not an arithmetic operation (-1) – Mårten W Oct 7 '13 at 13:59

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