I am currently working on a little extra credit for my 9th grade math class and I am stuck on the one of the problems.
The Three-Number Problem
I have chosen three numbers. The second is twice the first, and the third is three times the second. The sum of the first two when multiplied by the sum of the last two happens to be the same as the first number multiplied by the quare of the second number.
I decided to approach this by first starting with 3 variables.
f, s, and t.
f standing for the first number.
s standing for the second number.
t standing for the third number.
f = #
s = 2f
t = 3s
The equation I came up with was:
(f + s) * (s + t) = fs2
Which can be simplified to:
fs + ft + s2 = fs2
However, from there on, I am stuck. I have no idea how to solve for
f. However, i'm sure that i'm in the right place and that somebody here can help me out. Thank you!