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I'm currently trying to learn about Hochschild homology of differential graded algebras. After reading the definition, the notion of Hochschild homology is somewhat unmotivated and myterious to me. What is the motivation to define Hochschild homology and what are some nice examples?

I'm particularly interested in the Hochschild homology of truncated polynomial algebras $$k[x]/(x^{n+1})$$ where $k$ is a field of characteristic zero and $x$ is of some degree $d$.

Are there any nice references for Hochschild homology?

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You can try chapter 9 in Weibel's An Introduction to Homological Algebra, he does quite a lot there. Although not that much in terms of motivation. On the other hand, the definition seems pretty natural to me and not that dissimilar from e.g. de Rham cohomology or simplicial methods (and indeed there are connections to both as you can learn in Weibel). – Marek Oct 3 '13 at 13:32
You might take a look at the Hochschild-Kostant-Rosenberg THM: – mbrown Oct 3 '13 at 13:47
Also, Loday's Cyclic Homology is a nice reference. – mbrown Oct 3 '13 at 13:48
Writing down the Hochschild homology (HH) of the abstract $k$-algebra $k[x]/(x^{n+1})$ shouldn't be to hard. But I don't know how the HH of a DGA is defined (maybe it equals the HH of an abstract algebra if the DGA is concentrated in a single degree like yours ?). So can you please give the definition of HH of a DGA ? – Ralph Oct 3 '13 at 15:03
Thank you all for the references! – Dave Oct 3 '13 at 20:22
up vote 1 down vote accepted

Set $R = k[x]/(x^{n+1}),\,u=x\otimes 1-1\otimes x,\,v=\sum_{i=0}^n x^i\otimes x^{n-i} \in R^e := R \otimes_k R$.

First, let's recall from Weibel (Ex. 9.1.4) that in the ungraded case a projective resolution of $R$ over $R^e$ is given by the periodic complex $$\cdots \xrightarrow[]{v} R^e \xrightarrow[]{u} R^e \xrightarrow[]{v} R^e \xrightarrow[]{u} R^e \xrightarrow[]{\mu} R \to 0$$

Now suppose $R$ is a DGA with $\deg(x)=d$ and zero differentials. The latter implies that the notions of the Hochschild homology of $R$ as DGA and as graded algebra agree. Hence we can compute the Hochschild homology of $R$ by a projective resolution of $R$ over $R^e$ in the category of graded $R^e$-modules.

For a graded $R^e$-module $M$ let $\Sigma^kM$ be the shifted graded $R^e$-module given by $(\Sigma^kM)_i := M_{i-k}$. Set $e_k := (0,\ldots,1\otimes 1,\ldots 0) \in (\Sigma^kR^e)_k$. Then $\Sigma^kR^e=R^e\cdot e_k$ is a free graded $R^e$-module (in particular it's a projective object in the category of graded $R^e$-modules).

Taking into account $\deg u = d, \,\deg v=nd$, we can adjust the projective resolution from Weibel above and find the following projective resolution of $R$ over $R^e$ (taken in the category of graded $R^e$-modules): $$\cdots \to \Sigma^{(n+1)d}R^e \xrightarrow[]{d_2} \Sigma^dR^e \xrightarrow[]{d_1} R^e \to R \to 0$$ $$\cdots \to \Sigma^{(n+1)di}R^e\xrightarrow[]{d_{2i}}\Sigma^{(n+1)di-nd}R^e \xrightarrow[]{d_{2i-1}}\Sigma^{(n+1)d(i-1)}R^e\to\cdots $$ where $d_{2i}: e_{(n+1)di} \mapsto v\cdot e_{(n+1)di-nd},\,d_{2i-1}: e_{(n+1)di-nd} \mapsto u \cdot e_{(n+1)d(i-1)}$.

Now $HH_\ast(R,M)$ can be computed by tensoring this complex with $M$ (over $R^e$) and taking the homology. Using the relation $M \otimes_{R^e}\Sigma^kR^e=\Sigma^k M$ we obtain, for example, for $M=R$ the complex $$\displaystyle\cdots \to \Sigma^{(n+1)di}R\xrightarrow[]{d_{2i}}\Sigma^{(n+1)di-nd}R \xrightarrow[]{0}\Sigma^{(n+1)d(i-1)}R\to\cdots $$ where $d_{2i}: e_{(n+1)di} \mapsto (n+1)x^n\cdot e_{(n+1)di-nd}$. Hence

If $n+1$ is invertible in $k$ then (as graded $R$-module) $$HH_{2i}(R,R)=\Sigma^{(n+1)di}Rx,\quad HH_{2i-1}(R,R)=\Sigma^{(n+1)di-nd}R/(x^n), \quad H_0(R,R)=R.$$

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Thank you very much! It looks very interesting, I'll have to think about it some more. – Dave Oct 15 '13 at 15:02
You wrote that "[zero differentials] implies that the notions of the Hochschild homology of $R$ as a DGA and as a graded algebra agree." This seems to disagree with Loday's discussion in section 5.3.4 of Cyclic Homology: he writes "Note that if $\delta = 0$, then $HH$ and $HC$ of $(A,0)$ are not equal a priori to $HH$ and $HC$ of $A$ since the last face $d_n$ is not the same in the two cases. However if $A$ is concentrated in degree 0, then both theories agree." – JHF Mar 29 at 14:55
This looks great.Now my question is what does this compute? Is it seeking some holes? topological invariants etc, are there analogs of betti numbers and what not. It seems easy enough to construct but what does it mean? – kevin Tah N. Mar 30 at 9:37

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