# volume of right Parallelepiped

in a 3 day i have a national exam so i am trying to work hard i have one question from this link

http://www.naec.ge/images/doc/EXAMS/exams-2011-gat-5-ivlisi-.pdf


see problem 76. because it is written into Georgian i will translate it right now, problem is following:as you see right Parallelepiped which has dimension width=10cm and height=6cm is divided into 6 equal right Parallelepiped,we are asked to find volume of each one,sure one of the very simple method is find length calculate volume of original and then divide by 6 i think that for original Parallelepiped,width=10,height=6,and length=10 from figure it seems that base is regular ,so volume of each will be 100cm^3 but i am not sure please help me

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Since all of them are identical, from the image you can conclude that the height of each parallelepiped is $\frac{6}{3}=2$ and the width is $10$ and depth $\frac{10}{2}=5$. Hence the volume of each parallelepiped will be $2\cdot10\cdot5=100$ cm$^3$.
You were right to conclude that the full parallelepiped is $10 \times 10\times 6$. It follows from that, exactly as you wrote, that each piece has volume $100$ cm$^3$. You did not have the "wrong way", you had another right way.