# Combining Remainders in Divison

I am trying to find another way to approach a division problem than the typical long division approach.

For example: $876/32$. I am trying to break this division number into single digits only. for the the 3 $$8=3(2)+2$$ $$7=3(2)+1$$ $$6=3(2)+0$$ for the 2 $$8=2(4)+0$$ $$7=2(3)+1$$ $$6=2(3)+0$$

Knowing these value quiotents and their respective remainders. Is there a way to find the divion of this problem?

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How is this different from your last question? –  Michael Albanese Sep 27 '13 at 19:48
Given that the answer is $27$ remainder $12$ and there is no obvious $7$ on the right hand side of your sub-equations to give $27$, is there any particular reason you have for suggesting this might be true? Note also that your formulation does not work well with base $10$ - is there some base-invariant form of division you had particularly in mind? –  Mark Bennet Sep 27 '13 at 20:03