With the absorption law, I know I can do
$$P \land (P \lor Q) \equiv P$$
Can the same be applied like this?
$$(\lnot R \land P) \land (Q \lor P) \equiv P$$
Because, technically, I could move $Q$ to associate with the left parenthesis, and then switch its position with the first $P$, making this:
$$[(\lnot R \land Q)\land P] \lor P$$
Which looks a lot like the first scenario.