Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

If we know the rational homology of X is 0, can we get some information about the rational homology of X/G, where G is a finite group? Thank you very much for the answers!

share|cite|improve this question
up vote 6 down vote accepted

When $G$ is finite, the rational cohomology of $X/G$ is the fixed point set $H^*(X;\mathbb{Q})^G$. This is proven in Grothendieck's Tohoku paper (Theorem 5.3.1 and the Corollary to Proposition 5.3.2).

So if the rational cohomology of $X$ is trivial, the same is true for $X/G$. And rationally the cohomology and homology are isomorphic.

For paracompact Hausdorff spaces, these cohomology groups can be taken to be the Cech cohomology groups. Note that if $X$ is homotopy equivalent to a CW complex, then Cech cohomology agrees with singular cohomology. You might also want to look at Oscar Randall-Williams comments here:

share|cite|improve this answer
Dear Dan, since I "find" you here, I ask you the same question I've already asked you in MO (sorry for the duplicate): which result is this in the Tohoku paper? – a.r. Sep 17 '10 at 8:30
@Agusti, this is a consequence of the existence of a spectral sequence $H^\bullet(G,H^\bullet(X,\mathbb Z))\Rightarrow H^\bullet(X/G,\mathbb Q)$. It is discussed (in a general form) in the sixth section of the Tôhoku paper, iirc (I don't have my copy at hand) It can readily be proved onces you know about the Grothendieck spectral sequence (once you know that sheaf cohomology agrees with singular cohomology on your nice space) – Mariano Suárez-Alvarez Sep 17 '10 at 13:55
is it generaly true for $X$ being a manifold or more, orbifold?(they only have homotopy type of CW complex)? – abc Sep 17 '10 at 14:05
@Mariano. Thanks. As for the Tohoku paper, you can find it for free at Project Euclid:… and… . – a.r. Sep 17 '10 at 14:54
I edited here and on MO to include the more precise reference. Just to be clear, I am referring to the same part of the paper as Mariano (Chapter 5 is sort of the 6th section, if you count the introduction). – Dan Ramras Sep 17 '10 at 16:14

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.