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$g(t) = \sqrt{1 − 8^t}$

The domain of $g(t)$ is all the values of t for which $8^t ≤ 1$. To find the upper bound of this domain, I solve $8^t = 1$ and obtain that $t ≤ 0$? Is that correct? Thanks.

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up vote 0 down vote accepted

Yes, this is absolutely correct.

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