Is there any direct way to prove that $n$-manifold is orientable? In AT we can just calculate $n$'th homology group and check whether it's $\mathbb Z$ or $0$. But I want a geometric method, using differential forms. Thanks!
If you have a nowhere vanishing n-form, then the manifold is orientable.
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
5 years ago
4 years ago
Get the weekly newsletter! In it, you'll get:
see an example newsletter