# How many chess games are required to be played if 9 players win 2 games against each other player?

How many chess games are required to be played if 9 players win 2 games against each other player?

I got this because each player plays 8 games in 1 iteration (he cannot play against himself) and wins 1. To win 1 game against every player, he plays 64 games. To win 2 games against every player, he plays 128 games. However, there are 8 other players who do the same so there are (128*9) games played? Is this correct?

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To win a game against every player, (s)he plays $8$ games. –  André Nicolas Aug 16 '13 at 6:05
@andrénicolas so you're saying, 144 games are played? (8 games played for 1 player to win 1 game against everyone else, *2 to win 2 games which gives 16) There are 9 players so 16*9 = 144 –  user115422 Aug 16 '13 at 6:07

Each player has $16$ wins. There are $9$ players. Since there are no draws, the number of wins is the number of games.