Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

In an isosceles triangle ABC,AB=AC,P and Q are points on AC and AB respectively such that CB=BP=PQ=QA.Then prove that angle AQP=900/7

share|improve this question
2  
Please show work, and avoid "questions" that are merely the statement of a problem. –  The Chaz 2.0 Aug 10 '13 at 5:39

1 Answer 1

Hints: Make a drawing, then

$$\alpha:=\angle BCP=\angle ABC\;,\;\;\angle PBC=180^\circ-2\alpha\implies \angle QBP=3\alpha-180^\circ=\angle PQB\implies$$

$$\implies \angle AQP=360^\circ-3\alpha$$

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.