i would like to exactly what is asked in this problem:
The probability that A can solve the problem is $1/4$ and that B can solve it is $1/3$. If both of them try, what is the probability that problem will be solved.
i will say what is a point of my confusion,when we are trying to find probability of two independent events,we are multiplying probability of each other to get probability that both event occur .now first it is what i have tried and got $1/12$,but it shows me that it is not correct,now i have this question and please could help me,how can i translate if both of them will try into probability language?
$P(A or B)$ is not correct because it means that one or second will solve,so it means that $P(A and B)$,but they are independent are this would not be product of their probabilities?let us denote probability that $A$ will solve by $P(A)$, and probability that $B$ will solve by $P(B)$
now what would be $P(A and B)$?would not it be $1/4*1/3$?
or i am calculating wrongly and it would be $P(A or B)$