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Leg $XY$ of the right triangle is twice as long as leg $YZ.$ If the area of the triangle is $36cm^2$, what is the length, in cm, of leg $XY?$

I figured the answer out by applying $A= \dfrac{1}{2} (b \times h)$. $36 = \dfrac{1}{2} (b x h).$ Knowing that one leg is twice the length of the other leg, I just used $12$ and $6$ as I knew when multiplied it equals $72$ (before being multiplied by $1/2$). What is the correct formula for finding the answer to this problem? Thanks!

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up vote 1 down vote accepted

As you said $ \frac{1}{2} * b * h $

$ \frac{1}{2} * b * 2b = 36 $

$ b^2 = 36 $

$ b =6 $

This implies $ h = 12 $ as $ h = 2b $

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Thank you, Harish! I knew I was missing something! – dinoly333 Jul 29 '13 at 15:19
Ya If you feel that your doubt is allayed ,accept the answer . – Harish Kayarohanam Jul 29 '13 at 15:20

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