# new definition in graphs

I was reading a topic on wikipedia. There a product "corona product" was defined as :

Corona product of graphs $G_1$ and $G_2$, is the graph which is the disjoint union of one copy of $G_1$ and $|V_1|$ copies of $G_2$ ($|V_1|$ is the number of vertices of $G_1$) in which each vertex of the copy of $G_1$ is connected to all vertices of a separate copy of $G_2$.

What I am trying is... Suppose I take graph $G_1$ on 4 vertices. So, according to definition, I have to take 4 copies Of graph $G_2$, say $H_1,H_2,H_3, H_4$ and vertices of $G_1$ as $v_1,v_2,v_3,v_4$. What I understood about the product is that I will join $v_1$ with every copy of $H_1$ only, $v_2$ with every copy of $H_2$ only and so on..

Am I right in performing the product? If not, then please rectify me. Thanks a lot.

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Yes. I was unable to find the original paper, but all other articles do what you describe. Please note, that there is also a different version, the edge corona product (where you add $|E_1|$ copies of $G_2$). $G_1$ is usually called the center graph, while $G_2$ is named outer graph. In the following picture $G_1$ is yellow and $G_2$ is red.
$\hspace{70pt}$
I hope this helps $\ddot\smile$
@dtdarek ... So your figure is based when we take |V(G1)| copies of graph $G_2$. Am I right Sir? Thanks a lot for ur response sir –  monalisa Jul 29 '13 at 5:49
@monalisa We have $1$ copy of $G_1$ (yellow) and we have $|V(G_1)|$ copies of $G_2$ (red). Does this answer your question? –  dtldarek Jul 29 '13 at 5:54