If $\theta$ is in quadrant 1 and $\tan(\theta) = .6$ then $\sec(\theta) = $?
This seems pretty easy to me:
Another one, $\cos(\theta)=\sin(2\theta)$
Should that be $\cos^2(\theta)+\sin^2(\theta)=1/2$? Which would be .5
For all angles $\theta$, $\cos(-\theta)$ = $\cos(\theta)$
I said false how can I negative angle be equal to a positive one?
If $\sin^2(\theta)= .5$ then $(\sin(\theta))^2 = (\cos(\theta))^2$
I said false because $\sin$ and $\cos$ can never equal .5 together but it was wrong.
This answer is wrong but I don't understand why.
I am seriously considering changing majors, I know most people here will think I am an idiot, lazy or whatever else for taking such simple high school level math courses in college but I really am having trouble with it. I keep making mistakes no matter what I do I can never get better than a D or C on a test. So I am trying to evaluate the mistakes I made on the test so I don't make them again, but inevitably I will.