$\sec (3 \beta + 10) = \csc (\beta + 8)$ (in degrees)
I am supposed to find one solution, and the angles are acute.
I do not know the answer or how to get the answer.
It is confusing for me because I don't know what to do with the $3 \beta$.
I am guessing that maybe I get rid of the $\sec$ and $\csc$ somehow but I am not sure how I would go about doing that.