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I would like to find out the sum of the following series $$ \lim_{n\to\infty} \left[\frac{n^2}{{(n^2+1)}^{3/2}} + \frac{n^2}{{(n^2+2)}^{3/2}} + \dots + \frac{n^2}{{(n^2+(n+1)^2)}^{3/2}}\right] $$ now it would be just upto $n$ then I could have calculate with Riemann's integral by narrowing it and simplify then just integrate the definite integration. As it's upto $n+1$, I am having the trouble simplifying it. Any help?

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I think there is a mistake in your calculation. How did you reach to this sum? –  Mhenni Benghorbal Jun 21 '13 at 11:14
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1 Answer

up vote 3 down vote accepted

There are $n+1$ terms, and all but the last are at least $1/2$. So...

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Dont get iit!!! –  Tamim Ad Dari Jun 21 '13 at 11:00
    
What is the limit of $\dfrac{n+1}{2}$ as $n \to \infty$? –  Robert Israel Jun 21 '13 at 11:02
    
But maybe the real question was supposed to have $n$ instead of $n^2$ in the numerator. –  Robert Israel Jun 21 '13 at 11:02
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@RobertIsrael, there are $(n+1)^2$ terms, as I see. –  Oleg567 Jun 21 '13 at 11:06
    
Good point. So to get a nontrivial limit, you want $1$ in the numerator. –  Robert Israel Jun 21 '13 at 12:23
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