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$c = 2 , x = Range[1,3,1] , y = c*x^2$

What is the answer?

I don't know how to solve. can anybody help me to solve? Thanks.


this's the result : how this happen?

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Well, $$c = 2 , x = Range[1,3,1] , y = c*x^2$$ is not a question, so I don't know what you mean by "What is the answer?" Can you provide any context that would help other people figure out what you mean? – Zev Chonoles Jun 20 '13 at 21:08 it returns $x = {1,2,3}$ can anybody explain how this happen? – Elmi Ahmadov Jun 20 '13 at 21:15
Please give the context. – Tony Piccolo Jun 20 '13 at 23:03

2 Answers 2

There really is no mathematical problem here. I believe that the term Range in this context means that x ranges from 1 to 3 in steps of 1. That is why Wolfram returned the values of 1, 2 and 3 for x. If you are supposed to find values for y, then y = 2, 8, and 18, respectively when x = 1, 2 and 3.

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The $x$, $y$, and $z$ in Range[x, y, z] are called the min, max, and step respectively. It specifies the sequence of numbers $$x, x + z, x + 2z, \ldots$$ which starts at $x$, increases by $z$ each time, and stops after reaching $y$.

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